19 thoughts on “Algebra – 6

  1. In the Q2 shouldn’t the equation obtained be (n – 48)(m – 12)= 12*48

    Also on Factorization R.H.S will be 2^6*3^2
    And since they have asked for odd values of n the only possibility of L.H.S would be when the (n – 48) term is odd.
    Hence only factors 1, 3, 9 will be considered making corresponding n values – 49, 51, 57.
    I found this approach shorter 🙂

    • Valid point Prateek 🙂 I should have just said “alternative” and not “more efficient” I guess.

      The thought behind posting this approach was, if someone does not already know the factorisation approach, coming up with something like that on the spot would be tricky. Yet the answer could still be got logically without need of any very specialised knowledge 🙂 (The first time I encountered such a question, I solved it by this way and it was a couple of years later that I found out that there was a proper algebraic way as well!)

      regards
      J

    • The note in the previous post (algebra – 5) covers “finding all integer solutions”, Shivam. If you want with the limit on n, that also can be extrapolated – the negative solutions for n and all the positive odd ones less than 60. One would have to list out and eliminate, still not too lengthy…

      regards
      J

  2. Sir, In q2,if it was asked for negative solns as well, then what would have been the process (from prateek’s soln. point of view)

  3. Sir, In Q 1, (y+40) can’t take values 0,2,3,4,5,8,10,12,15,16,20 and so on all the factors till 40. So should we rule out those values also ?? The answer should not be 36 . If it is so, kindly tell me my mistake.. 🙂 TIA

  4. Sidharth, you’re right, my bad – I solved for y+40 to be a positive integer. There would be around 19 solutions I guess. I have edited it accordingly… thanks for pointing out!

    regards
    J

  5. sir ,can u please help me in this 2 question .
    1.how to find total negative term of (a-b+c)^2003 ? with detail procedure.
    2. find the no. of term (1+X^2+x^4)^40 ? with detail explanation .

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