16 thoughts on “Modulus Functions in Two Variables – 6

  1. Dear J,

    I would like to thank u a lot for the effort you are taking in each post. These posts have truly helped me in many ways for which i am grateful. I am having my CAT on Nov.1 and hope the methods taught here will come in more handy( as you have already saved us with the ant question ). 🙂


  2. Sir after getting the range like x=2,3,4,5,6 and y=0,1,2,3,4 do we have to check after plugging each and every value or i there any quicker method in this to obtain. I mean do we need to form all the combination at hand to get the result.

  3. Yes, I missed that one.
    As you have pointed out in the post that the only difference between them is their centres, so I was checking the solutions….
    So, effectively, in the test, can we solve for |x| + |y| = 5, if the question is |x+5| + |y-3| = 5? ;)(Integer co-ordinates)

    Regards 🙂

  4. What goes wrong if we were to plot the graphs for the 2 variables, |x-4| and |y-2|, separately, in a way similar to the previous post on modulus addition? Thank You! These topics have been of great of help.

  5. The problem is, how would you do that? Normally if you are plotting just |x-4| it means you are plotting y = |x-4| and so here you would be trying to do two separate things, both in x and y. Confusing. Here both x and y are interacting together and we can’t separate them out that easily since both are within modulus signs. So trial and error is simplest.


  6. Here, just draw the graph of |x|+|y|=5 and then shift the graph according to the given point and we know the graph of this given mod is simple rhombus .Using the concept of 90-45-45 find its one of the side which will be equal to the 5sqrt2=50.

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