23 thoughts on “Modulus Examples -1

  1. Dear J,

    Is the no: of integer points = 37? i.e X varies from -3 to 3 right? And the is the figure in the form of a triangle seated on top of a rectangle?

    Thanks,
    Jan

  2. Dear J,

    So plotting them will give a triangle of base -3 to +3 and height 0 to 3 and a rectangle of sides -3 to 3 and 0 to -3. By this iam getting area as 42 i.e 7 * 4 + 0.5 * 7 * 4. What am i doing wrong here?

    Thanks,
    Jan

  3. for x = -2, we can also get y= -4, as:
    -2 -y -(2+y) = 4,
    which gives -2y = 8,
    y= -4
    because when value from modulus is considered, it will be negative? this way for one value, many values of y can come.. whats wrong in it?

  4. ohh.. ok, actually i intentionally took it because i thought negatives will be taken as it is, like we do in modulus , if |x| <= 5, then we take -5<x<5, like that.. anyways,, thanks

  5. sir, i am having hard time for getting the range for values here…like for x=2, i am getting 2y=0 so y=0 correct…then what should be the next step to get y=-2…if i open the mod as -2-y-y-2=4 then i am getting y=-4…what step i am doing wrong here…?

    • Hi Sir,

      Thanks again for the wonderful post.
      I have one query with regards to finding the range for x and y.
      I have understood that the basic concept you are using for the same is making sure mod of x or y should not be equal to a negative number, that’s where you stop.
      Having said that for the equation lxl+lyl+lx+yl=4 when I sub x=3 I get the values of y=-1,-2.
      Now just looking at the values of y I am not able to say if it as acceptable value or not.
      I did substitute back to the main equation and find out that it was not satisfying the equation hence I could discard this value.
      Is this the way you are following too?
      Could you please help me on this.

      • Not exactly. In lxl+lyl+lx+yl=4 when I put x=3 I get l3l+lyl+l3+yl=4 which is |y| + |y+3| = 1 which gives no values (the sum of the distances of y from 0 and 3 should add up to 1, which is not even possible!). But yeah, it is always safer to check your answer by plugging back in, if time permits.

        regards
        J

  6. sir like for x=2 first i am doing putting |x| as x and getting y=0 as result then putting |x| as -x …for this i am getting y=-4 but the range is from -2 to 0 …i know i am making a very silly mistake but please can you point me to it…

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

w

Connecting to %s