Suppose I assume the people as a,b,c,d,e such that a<b<c<d Timmy)
6[a+b+c+d+e] = 840 a+b+c+d+e = 840/6 = 140
a+b+c = 60 (20*3)
a+b+d = 72 (24*3)
a+b+e = 75

a+b+2c+d+e = 165
a+b+c+d+e = 140
c = 25

a+b = 35

Now a+b+e = 75

e is 40 in that case.

Please point out what I’m missing here

Why have you assumed a + b + e = 75? That could equally be a + c + d?

Sir I have a doubt, please help!

Suppose I assume the five people as a,b,c,d,e such that a<b<c<da+b=35

Why is e (which is the highest, that is Timmy) not 43 but 40 in this method? What am I missing here? Someone please point out

Not sure where you got 40 from randomly, could you explain?

regards

J

Suppose I assume the people as a,b,c,d,e such that a<b<c<d Timmy)

6[a+b+c+d+e] = 840 a+b+c+d+e = 840/6 = 140

a+b+c = 60 (20*3)

a+b+d = 72 (24*3)

a+b+e = 75

a+b+2c+d+e = 165

a+b+c+d+e = 140

c = 25

a+b = 35

Now a+b+e = 75

e is 40 in that case.

Please point out what I’m missing here

Why have you assumed a + b + e = 75? That could equally be a + c + d?

regards

J