Hi, sorry again for the noob doubt but for (6-x)^4 and (2-x)^5, how are the roots 6 and 2 instead of -6 and – 2? For (6-x) the power is positive hence (6-x)^4 will be (x-6)^4 hence understandable but can’t understand for (2-x)^5.
What is a root? A place where the function becomes zero. For that, the value in one of the brackets must be zero. Now, at what value of x will the bracket (6 – x), and its powers, become 0? 6 or -6?
in the cat concept i read if the corresponding power is even we do not change the sign… just wanted to confirm that you have applied the similar concept?
CAT-holics 
Hi, sorry again for the noob doubt but for (6-x)^4 and (2-x)^5, how are the roots 6 and 2 instead of -6 and – 2? For (6-x) the power is positive hence (6-x)^4 will be (x-6)^4 hence understandable but can’t understand for (2-x)^5.
What is a root? A place where the function becomes zero. For that, the value in one of the brackets must be zero. Now, at what value of x will the bracket (6 – x), and its powers, become 0? 6 or -6?
regards
J
Voted my question 1 star after realizing how stupid it was! 🙂
Thanks for responding!
in the cat concept i read if the corresponding power is even we do not change the sign… just wanted to confirm that you have applied the similar concept?
Yes, I have just tried to explain the “why” of it, for those who might be interested.
regards
J