Hi, sorry again for the noob doubt but for (6-x)^4 and (2-x)^5, how are the roots 6 and 2 instead of -6 and – 2? For (6-x) the power is positive hence (6-x)^4 will be (x-6)^4 hence understandable but can’t understand for (2-x)^5.

What is a root? A place where the function becomes zero. For that, the value in one of the brackets must be zero. Now, at what value of x will the bracket (6 – x), and its powers, become 0? 6 or -6?

in the cat concept i read if the corresponding power is even we do not change the sign… just wanted to confirm that you have applied the similar concept?

Hi, sorry again for the noob doubt but for (6-x)^4 and (2-x)^5, how are the roots 6 and 2 instead of -6 and – 2? For (6-x) the power is positive hence (6-x)^4 will be (x-6)^4 hence understandable but can’t understand for (2-x)^5.

What is a root? A place where the function becomes zero. For that, the value in one of the brackets must be zero. Now, at what value of x will the bracket (6 – x), and its powers, become 0? 6 or -6?

regards

J

Voted my question 1 star after realizing how stupid it was! ðŸ™‚

Thanks for responding!

in the cat concept i read if the corresponding power is even we do not change the sign… just wanted to confirm that you have applied the similar concept?

Yes, I have just tried to explain the “why” of it, for those who might be interested.

regards

J