In the 1st example, isn’t the 11th point the starting point?
let x = 28
((7 * 11 * 28)/11) % 28 = 0
whereas if n=12
((7 * 12 * 28)/11) % 28 = 17.81
which is the same when n=1
The answer will remain same because the starting point (n=0) was not counted.
Yes, isn’t that the same as what I said? After 11 meetings, they will be back to the starting point.
I mistunderstood ‘after 11 meetings’ as ‘at the 12th meeting’
Can we have a shortcut as adding the ratios for no. of distinct points.
Effectively, yes, as long as the ratio is in the most reduced form (so if the speeds are 4 and 6, we will have to first make it 2 : 3)
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