In the 1st example, isn’t the 11th point the starting point? let x = 28 if n=11 ((7 * 11 * 28)/11) % 28 = 0 whereas if n=12 ((7 * 12 * 28)/11) % 28 = 17.81 which is the same when n=1 The answer will remain same because the starting point (n=0) was not counted. Reply

Yes, isn’t that the same as what I said? After 11 meetings, they will be back to the starting point. regards J Reply

Effectively, yes, as long as the ratio is in the most reduced form (so if the speeds are 4 and 6, we will have to first make it 2 : 3) regards J Reply

In the 1st example, isn’t the 11th point the starting point?

let x = 28

if n=11

((7 * 11 * 28)/11) % 28 = 0

whereas if n=12

((7 * 12 * 28)/11) % 28 = 17.81

which is the same when n=1

The answer will remain same because the starting point (n=0) was not counted.

Yes, isn’t that the same as what I said? After 11 meetings, they will be back to the starting point.

regards

J

Oh..

I mistunderstood ‘after 11 meetings’ as ‘at the 12th meeting’

Can we have a shortcut as adding the ratios for no. of distinct points.

Effectively, yes, as long as the ratio is in the most reduced form (so if the speeds are 4 and 6, we will have to first make it 2 : 3)

regards

J