Right Sakshi, I will edit it. The original problem I had chosen had a minus in the quadratic, yielding positive roots ðŸ˜› regards J Reply

where is the negative value of x?? the basic form of a quadratic equation is x^2 -(a+b)x + a*b = 0 ; where ‘a’ and ‘b’ are the roots and a*b is the product of their multiplication. In question 4, the roots and +2 and +3 ( not negative). Reply

As mentioned in the earlier comment, I have edited the post. In the original version, the roots were negative… regards J

But in question 4, x cannot take negative value ..so we have no solution. Right?

Right Sakshi, I will edit it. The original problem I had chosen had a minus in the quadratic, yielding positive roots ðŸ˜›

regards

J

where is the negative value of x?? the basic form of a quadratic equation is x^2 -(a+b)x + a*b = 0 ; where ‘a’ and ‘b’ are the roots and a*b is the product of their multiplication. In question 4, the roots and +2 and +3 ( not negative).

As mentioned in the earlier comment, I have edited the post. In the original version, the roots were negative…

regards

J