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Right Sakshi, I will edit it. The original problem I had chosen had a minus in the quadratic, yielding positive roots 😛 regards J Reply
where is the negative value of x?? the basic form of a quadratic equation is x^2 -(a+b)x + a*b = 0 ; where ‘a’ and ‘b’ are the roots and a*b is the product of their multiplication. In question 4, the roots and +2 and +3 ( not negative). Reply
As mentioned in the earlier comment, I have edited the post. In the original version, the roots were negative… regards J
CAT-holics 
But in question 4, x cannot take negative value ..so we have no solution. Right?
Right Sakshi, I will edit it. The original problem I had chosen had a minus in the quadratic, yielding positive roots 😛
regards
J
where is the negative value of x?? the basic form of a quadratic equation is x^2 -(a+b)x + a*b = 0 ; where ‘a’ and ‘b’ are the roots and a*b is the product of their multiplication. In question 4, the roots and +2 and +3 ( not negative).
As mentioned in the earlier comment, I have edited the post. In the original version, the roots were negative…
regards
J