11 thoughts on “Sequences – CAT Scan 4

  1. In your second question (n-1)d=999 why it has to be that d has to be factors of 999? Is it because any other no. will leave a fraction and we wont get a natural number?

    • We are not taking n = 999. We are taking (n-1)d = 999. Read it carefully (if need be, revisit the original post about APs)
      And we are not eliminating the numbers 1 and 1000. We are eliminating the AP (1, 1000). That is because (1, 1000) is an AP with 2 terms and the question specifically asks “at least 3 terms”.

      regards
      J

    • Well we could do 1r^n = 1000. This would give us only r as 10 or 1000 as a feasible alternative. But r = 1000 would give a 2 term GP. So there would be only that 1 GP with more than 2 terms, viz 1, 10, 100, 1000.

      regards
      J

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