SIR , there is another shortest path problem of a solid cuboid…
an ant starts at one lower corner.. and wants to reach the diagonally opposite corner of the upper edge of the opposite face…
and it comes out that path is shortest when it passes through midpoint of sides… for not just opposite face , any face!
Girish, the midpoint would only be for a cube. For a random cuboid, it would have to be checked a bit more carefully. And coincidentally, tomorrow’s post will cover precisely that 😀
Thank You Sir
its a base ques quite simple but coudnt get it . What is the number of zeroes at the end of 100! if it is expressed in base 21?
Shalini, the numbers of zeroes in a base is equivalent to the highest power of that base present in the original number. So 21 = 3 * 7. Now the highest power of 3 in 100! is 48 whle that of 7 is 16 (lower than 48 and hence the limiting case) and hence the highest power of 21 is also going to be 16. So there should be 16 zeroes I guess.
Thnk u so much 🙂
LIKE FOR NOS. IN BASE 2.. WE WILL HAVE TO CHCK WD 2 DEN ??
Sir, shouldn’t it be 7 pi, not 14 pi in the last example ?
sir i am having hard time visualizing the second one…..i am thinking if we cut along the PB path and then hammer down the half cylinder, the 28cm should be double ??what part of my logic is wrong?
I am not sure what you mean – but I suspect either you are changing the shape of the figure or else trying to go through the interior. The ant must crawl, not fly.
but sir how the PA length got half,what i was meaning by the above comment is for the ant to crawl what if the cylinder got cut be by half along PB then to visualize how the rectangle is made the cylinder is hammered down to be a rectangle so PA should be greater that 28 in that scenario…
Fold a piece of A4 paper to make a hollow cylinder. Identify the points for the ant and the jam. Open it up. You will get your answer.
Yes….got it now…thanks much….!!
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