Inverted componendo – If a/b=c/d, invert this now ,b/a=d/c and then use componendo formula ,b+a/a=d+c/c .This is inverted componendo. I hope it helps you.

v/w = c/b
Now use inverted componendo [ 2/3 = 4/6 –> 2/(2+3) = 4/(4+6) right?.. similar ]
v/(v+w) = c/(c+b)
But from the figure, v+w=a
So, v/a = c/(c+b)
v= a. c/(c+b) ðŸ™‚

For the first question, a slightly simpler way would be to consider Triangle AOB.
Angle ABO = 45 ( Since angle bisected there) We can directly get Angle BAO ðŸ™‚

Hello Sir,

Can you please explain this step v = a*(c/(c+b)). I am not able to understand as how you arrived on this step from the previous one:

If I have to divide a in the ratio b : c then it will be a * b/(b+c) and a * c/(b+c) by standard ratio logic…

(For example if I have to divide 40 in the ratio 3 : 5 I will do 40 * 3 / 8 and 40 * 5 / 8, right?)

regards

J

Hey,

I did not understand how (w*c/b) became (a*c/(c+b))

Inverted componendo – If a/b=c/d, invert this now ,b/a=d/c and then use componendo formula ,b+a/a=d+c/c .This is inverted componendo. I hope it helps you.

a = v+w and inverted componendo should do the trick ðŸ™‚

regards

J

didn’t get the last comment of yous. Can you please elucidate ? ðŸ™‚

v/w = c/b

Now use inverted componendo [ 2/3 = 4/6 –> 2/(2+3) = 4/(4+6) right?.. similar ]

v/(v+w) = c/(c+b)

But from the figure, v+w=a

So, v/a = c/(c+b)

v= a. c/(c+b) ðŸ™‚

For the first question, a slightly simpler way would be to consider Triangle AOB.

Angle ABO = 45 ( Since angle bisected there) We can directly get Angle BAO ðŸ™‚

True ðŸ™‚ Nice spot!

regards

J