Inverted componendo – If a/b=c/d, invert this now ,b/a=d/c and then use componendo formula ,b+a/a=d+c/c .This is inverted componendo. I hope it helps you.
v/w = c/b
Now use inverted componendo [ 2/3 = 4/6 –> 2/(2+3) = 4/(4+6) right?.. similar ]
v/(v+w) = c/(c+b)
But from the figure, v+w=a
So, v/a = c/(c+b)
v= a. c/(c+b) 🙂
For the first question, a slightly simpler way would be to consider Triangle AOB.
Angle ABO = 45 ( Since angle bisected there) We can directly get Angle BAO 🙂
CAT-holics 
Hello Sir,
Can you please explain this step v = a*(c/(c+b)). I am not able to understand as how you arrived on this step from the previous one:
If I have to divide a in the ratio b : c then it will be a * b/(b+c) and a * c/(b+c) by standard ratio logic…
(For example if I have to divide 40 in the ratio 3 : 5 I will do 40 * 3 / 8 and 40 * 5 / 8, right?)
regards
J
Hey,
I did not understand how (w*c/b) became (a*c/(c+b))
Inverted componendo – If a/b=c/d, invert this now ,b/a=d/c and then use componendo formula ,b+a/a=d+c/c .This is inverted componendo. I hope it helps you.
a = v+w and inverted componendo should do the trick 🙂
regards
J
didn’t get the last comment of yous. Can you please elucidate ? 🙂
v/w = c/b
Now use inverted componendo [ 2/3 = 4/6 –> 2/(2+3) = 4/(4+6) right?.. similar ]
v/(v+w) = c/(c+b)
But from the figure, v+w=a
So, v/a = c/(c+b)
v= a. c/(c+b) 🙂
For the first question, a slightly simpler way would be to consider Triangle AOB.
Angle ABO = 45 ( Since angle bisected there) We can directly get Angle BAO 🙂
True 🙂 Nice spot!
regards
J