May 27, 2013 by catcracker Derangements – Introduction Share this:TwitterFacebookLike this:Like Loading... Related
In 5 objects in 5 position how is derangement of other 2 only matters when choosing only one correct. Doesn’t the other 4 matters.I also would like to know how can we get nine derangements.
Should have been other 4, hence the 9. Similarly previous line should have been “other 3”
The probability she managed to get 9 right equals to getting 10 right should be 1/10!
EXACTLY 9 right…