May 27, 2013 by catcracker Derangements – Introduction Share this:TwitterFacebookLike this:Like Loading... Related
In 5 objects in 5 position how is derangement of other 2 only matters when choosing only one correct. Doesn’t the other 4 matters.I also would like to know how can we get nine derangements. Reply
Should have been other 4, hence the 9. Similarly previous line should have been “other 3” regards J Reply
CAT-holics 
In 5 objects in 5 position how is derangement of other 2 only matters when choosing only one correct. Doesn’t the other 4 matters.I also would like to know how can we get nine derangements.
Should have been other 4, hence the 9. Similarly previous line should have been “other 3”
regards
J
The probability she managed to get 9 right equals to getting 10 right should be 1/10!
EXACTLY 9 right…
regards
J