J, can you help me wi this qn.
A new york city cab had a hit and run. Out of the 5 witnesses, 4 said the colourbof the cab was green and one said it to be yellow. The probability that the colour was rightly identified was 2/3. If 85% of the registered cabs in new york are yellow and 15% is green what is the probability that cab is green in colour
“The probability that the colour was rightly identified was 2/3.” This sentence seems to introduce some ambiguity (the interpretation I take from it seems incompatible with the other information given). Otherwise it seems to be the kind of problem one would solve by making a tree.
Can u pls help me with the below Ques.
Three friends have their bdays in same week but on different days. What is the probability that two of them will have their bdays on weekdays and one of them has it on weekend?
Applying first principles:
Sample space = 7x7x7 = 343.
Favourable cases: 3 ways of choosing which one is on the weekend, 2 ways for that person and 5 ways each for the rest = 3 x 2 x 5 x 5 = 150
So I guess it should be 150/343
Fill in your details below or click an icon to log in:
You are commenting using your WordPress.com account. ( Log Out / Change )
You are commenting using your Twitter account. ( Log Out / Change )
You are commenting using your Facebook account. ( Log Out / Change )
You are commenting using your Google+ account. ( Log Out / Change )
Connecting to %s
Notify me of new comments via email.