Sir do we have any rule in solving log problems like this: log(4)6= 1/2 log (2)6 just for example sake where ( ) represents base i mean converting bases. Like we have rule log(a)b^c= c log(a)b but anything for the base conversion. Please explain! Reply
Remember that log (b)a = log a / log b So the given expression is log 6 / log 4 = log 6 / 2 log 2 = 1/2 (log 6 / log 2 ) = 1/2 log (2) 6 You can make a standard formula out of this if you like! I prefer to just understand the logic and apply directly… regards J Reply
Sir do we have any rule in solving log problems like this:
log(4)6= 1/2 log (2)6 just for example sake
where ( ) represents base
i mean converting bases.
Like we have rule log(a)b^c= c log(a)b but anything for the base conversion. Please explain!
Remember that log (b)a = log a / log b
So the given expression is
log 6 / log 4 = log 6 / 2 log 2 = 1/2 (log 6 / log 2 ) = 1/2 log (2) 6
You can make a standard formula out of this if you like! I prefer to just understand the logic and apply directly…
regards
J
Thanks a lot!