Sir do we have any rule in solving log problems like this: log(4)6= 1/2 log (2)6 just for example sake where ( ) represents base i mean converting bases. Like we have rule log(a)b^c= c log(a)b but anything for the base conversion. Please explain! Reply

Remember that log (b)a = log a / log b So the given expression is log 6 / log 4 = log 6 / 2 log 2 = 1/2 (log 6 / log 2 ) = 1/2 log (2) 6 You can make a standard formula out of this if you like! I prefer to just understand the logic and apply directly… regards J Reply

Sir do we have any rule in solving log problems like this:

log(4)6= 1/2 log (2)6 just for example sake

where ( ) represents base

i mean converting bases.

Like we have rule log(a)b^c= c log(a)b but anything for the base conversion. Please explain!

Remember that log (b)a = log a / log b

So the given expression is

log 6 / log 4 = log 6 / 2 log 2 = 1/2 (log 6 / log 2 ) = 1/2 log (2) 6

You can make a standard formula out of this if you like! I prefer to just understand the logic and apply directly…

regards

J

Thanks a lot!