While solving the second question – you have eliminated the fraction without multiplying it with 2^x, isnt that wrong? Reply

I am not sure what you mean – I have just substituted the values of 2^x which I got and saw that it is not defined for one of those value (since log of a negative number, as mentioned in an earlier post, is not defined) regards J Reply

While solving the second question – you have eliminated the fraction without multiplying it with 2^x, isnt that wrong?

I am not sure what you mean – I have just substituted the values of 2^x which I got and saw that it is not defined for one of those value

(since log of a negative number, as mentioned in an earlier post, is not defined)regards

J