2 thoughts on “Logs – 8

  1. While solving the second question – you have eliminated the fraction without multiplying it with 2^x, isnt that wrong?

    • I am not sure what you mean – I have just substituted the values of 2^x which I got and saw that it is not defined for one of those value (since log of a negative number, as mentioned in an earlier post, is not defined)

      regards
      J

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