Sir in 9x-x^2-14 question, you are getting (x-2)(x-7)>0 but you are writing the solution for the case (x-2)(x-7)<0 as 2< x <7 Reply

sir for the last question the statement should have been if three numbers are in gp then their log will be in AP leme know if im wrong Reply

Sir in 9x-x^2-14 question,

you are getting

(x-2)(x-7)>0

but you are writing the solution for the case (x-2)(x-7)<0 as 2< x <7

Yes that is -(x-2)(x-7)>0 so should be (x-2)(x-7)<0. Typo ðŸ™‚

regards

J

sir for the last question the statement should have been

if three numbers are in gp then their log will be in AP

leme know if im wrong

Yes, Gaurav, you’re right…

regards

J