Sir in 9x-x^2-14 question, you are getting (x-2)(x-7)>0 but you are writing the solution for the case (x-2)(x-7)<0 as 2< x <7 Reply
sir for the last question the statement should have been if three numbers are in gp then their log will be in AP leme know if im wrong Reply
CAT-holics 
Sir in 9x-x^2-14 question,
you are getting
(x-2)(x-7)>0
but you are writing the solution for the case (x-2)(x-7)<0 as 2< x <7
Yes that is -(x-2)(x-7)>0 so should be (x-2)(x-7)<0. Typo 🙂
regards
J
What is the required range in the question? x<2 ?
sir for the last question the statement should have been
if three numbers are in gp then their log will be in AP
leme know if im wrong
Yes, Gaurav, you’re right…
regards
J