4 thoughts on “Triangles – Area Formulae

  1. Sir but area of the triangle is 1/2 bc*sin a, if we draw the triangle we come to know that sin a = a/2r… so substituting we get abc / 4r

    • Girish, you’re right, that’s a fair bit simpler than the method I used (proved it painfully from scratch – I learnt this formula before the 1/2 * absinC formula!). However, your method too requires the inscribed angle theorem and similar triangles to prove that sinA = a/2R 🙂 So I still stand by at least part of what I said 😉

      regards
      J

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

w

Connecting to %s