For last question the approach you gave is great. No doubt!!
But can the thinking go like this as A has lost most of the seats then assume total seats as 19 and calculated wins for each and see if we get total wins comes out to19??
Sure 🙂 However, this was a simplified version of the original question, which had numbers in the 3-digit range (150, 200, 250 types). So this approach would enable even that to be solved orally.
CAT-holics 
Hello J,
I am confused with the language of the 2nd question. Can you clear?
Thanks and Regards,
Vaibhav
It looks Like X has 5/3 times the money Y has.
i.e. if Y has money = p
then X has money = 5P/3
and 5p/3-P =40 so P =60.
So Y has 60 and X has 100.
Yes Vaibhav, 40 is the difference. Y has 60 indeed. Typo 🙂
regards
J
“Happy as a dog with a bone to chew”. XD 😀
Sir, you write very good. If there are any blogs you write, plz share.
Regards,
RZ
Hello J,
For last question the approach you gave is great. No doubt!!
But can the thinking go like this as A has lost most of the seats then assume total seats as 19 and calculated wins for each and see if we get total wins comes out to19??
Sure 🙂 However, this was a simplified version of the original question, which had numbers in the 3-digit range (150, 200, 250 types). So this approach would enable even that to be solved orally.
regards
J