11 thoughts on “Trapezium – Examples 2

  1. Can you let me know the solution , as i am able to solve using area of
    triangle and taking radius. is there any fast way to solve this

  2. Another useful property of Trapezium:
    “Sum of the squares of the length of the diagonals = Sum of squares of lateral sides + 2 x product of bases.”
    Diagonals AC^2 = BD^2 = 8^2 – 2^2 = 60

    Using above property: AC^2 + BD^2 = AB^2 + CD^2 + 2 x AC x BD
    60 + 60 = 4 + 4 + (2 x 8 x BC)
    l(BC) = 7

    Very handy for both questions.
    Source: HandaKaFunda

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