In CAT, even this level questions have rarely come. A XAT is more likely to ask something on these lines (or occasionally tougher); in areas like Arithmetic and Probability XAT often goes a fair bit tougher than CAT. CAT would go tough in Numbers and Functions…
sir,
B climbs effectively 2 steps forward in 4 s. Can’t we consider his effective speed to be 0.5 steps/s? If that is true then the number of steps he climbs in 118 s will be 59 steps. Where is the conceptual flaw?
Because it is not a constant speed. Some time he is moving forward, som time backward. Direct scaling (unitary approach) will work here only if the time is a multiple of his complete cycle time (the time after which his actions repeat, in this case 4 seconds)
You are misreading the RHS 🙂 The thought process is not (2 x 30)/(n-30). It is basically 2 x [30/(n-30)] implying that the second case speed is 2 x (first case speed).
why in first question, we can’t compare his normal speed? e.g. 18/n-18 = 30/n-30.
I know above written expression is dead expression, but still I am not able to deny it.
Can you please help me understand it ?
Sir,In the second question,the net effect of his speed is 2F,like essentially he takes 2 steps so why cant be divide 118 by 2 to get his distance traveled?
We can do that only if it is smooth movement. Not when it is forward and backward movement. Google “Frog in well puzzle” to get an idea of how that complicates things.
CAT-holics 
Really helpful
I didnt understand the last step of first sum …36/(n-36) =2*30/(n-30) .please explain
SUPER ONE.
UNDERSTOOD
Sir, have tougher questions than these appeared in CAT? Or is this around “CAT level”?
In CAT, even this level questions have rarely come. A XAT is more likely to ask something on these lines (or occasionally tougher); in areas like Arithmetic and Probability XAT often goes a fair bit tougher than CAT. CAT would go tough in Numbers and Functions…
regards
J
J,
From where shall we find more such questions to practice for all the topics?
Anywhere you can! Just search…or make up your own.
regards
J
sir,
B climbs effectively 2 steps forward in 4 s. Can’t we consider his effective speed to be 0.5 steps/s? If that is true then the number of steps he climbs in 118 s will be 59 steps. Where is the conceptual flaw?
Because it is not a constant speed. Some time he is moving forward, som time backward. Direct scaling (unitary approach) will work here only if the time is a multiple of his complete cycle time (the time after which his actions repeat, in this case 4 seconds)
regards
J
Sir, in the first problem
We are doubling 18steps to make it 36 and dividing it by n-36 . Then why aren’t we dividing 30*2 by n-60?
You are misreading the RHS 🙂 The thought process is not (2 x 30)/(n-30). It is basically 2 x [30/(n-30)] implying that the second case speed is 2 x (first case speed).
regards
J
Thank you sir
Great questions. Thanks.
Sir,
why in first question, we can’t compare his normal speed? e.g. 18/n-18 = 30/n-30.
I know above written expression is dead expression, but still I am not able to deny it.
Can you please help me understand it ?
Because he takes 36 steps not 18.
regards
J
Sir,In the second question,the net effect of his speed is 2F,like essentially he takes 2 steps so why cant be divide 118 by 2 to get his distance traveled?
We can do that only if it is smooth movement. Not when it is forward and backward movement. Google “Frog in well puzzle” to get an idea of how that complicates things.
regards
J