Jaikamal, it will not matter, as they are traveling perpendicular to the stream. Water speed will affect them differently in different directions only if traveling parallel to it. Here it will create the same drag whichever side they are moving so net effect is 0 (or rather can be neglected)

If both move at constant speeds, and in total they have covered 3 times as much distance by the second meeting, then each of them individually has covered 3 times as much. Make a small model of the swimming pool and convince yourself.:)

Sir, If you are considering 3 times of 120 since P travels thrice his distance then we get 360, however, it only traveled 90 when it returned for the second time and hence traveled 30 less (120-90). So shouldn’t the total distance be 360-30= 330. Can you please explain as to why you subtracted 90 from 360 instead of just the additional 30.

Sir, If you are considering 3 times of 120 since P travels thrice his distance then we get 360, however, it only traveled 90 when it returned for the second time and hence traveled 30 less (120-90). So shouldn’t the total distance be 360-30= 330. Can you please explain as to why you subtracted 90 from 360 instead of just the additional 30.

Sir I have a doubt in this. You said that if the speed is constant then the distance travelled individually by them would be in same multiplication of the total distance travelled by both of them ( i.e. 3) But dont you think it is valid when you start from the same point or in this case it can be applied after they met for the 1st time. its like to problem of fixed and variable part. You have to cover certain fixed amount and then after that it becomes linearly proportional.

I am not sure what exactly you are trying to say, but it certainly won’t be analogous to a fixed-variable situation. In TSD, unless otherwise stated, the speed of each individual in the problem remains constant.

In this question, the information regarding still water is missing.

Jaikamal, it will not matter, as they are traveling perpendicular to the stream. Water speed will affect them differently in different directions only if traveling parallel to it. Here it will create the same drag whichever side they are moving so net effect is 0 (or rather can be neglected)

regards

J

sir, how have you concluded that P travels 3 times the distance for the second meeting??

sir,P travels 3 times the distance for the second meeting?

Could you elaborate

If both move at constant speeds, and in total they have covered 3 times as much distance by the second meeting, then each of them individually has covered 3 times as much. Make a small model of the swimming pool and convince yourself.:)

regards

J

how it covered P covered d+90 in second trip

Sir, If you are considering 3 times of 120 since P travels thrice his distance then we get 360, however, it only traveled 90 when it returned for the second time and hence traveled 30 less (120-90). So shouldn’t the total distance be 360-30= 330. Can you please explain as to why you subtracted 90 from 360 instead of just the additional 30.

Sir, If you are considering 3 times of 120 since P travels thrice his distance then we get 360, however, it only traveled 90 when it returned for the second time and hence traveled 30 less (120-90). So shouldn’t the total distance be 360-30= 330. Can you please explain as to why you subtracted 90 from 360 instead of just the additional 30.

If you go from home to college, and then drive 1 km back, and find that your total distance driven is 10 km, how far away is your school?

regards

J

School would 5 km away. Is it correct Sir ?

No. Please read carefully, and think.

9 km away!

Sir I have a doubt in this. You said that if the speed is constant then the distance travelled individually by them would be in same multiplication of the total distance travelled by both of them ( i.e. 3) But dont you think it is valid when you start from the same point or in this case it can be applied after they met for the 1st time. its like to problem of fixed and variable part. You have to cover certain fixed amount and then after that it becomes linearly proportional.

I am not sure what exactly you are trying to say, but it certainly won’t be analogous to a fixed-variable situation. In TSD, unless otherwise stated, the speed of each individual in the problem remains constant.

regards

J

Thanks J.

You are the King.