Could you please help me understand how you found the lower limit i.e x should be greater than 4/9. I did refer to the previous post as well.But I am not clear with it.
Thanking you in advance.

Could you please help me understand how you got the lower limit as greater than 4/9. I did try going through the previous post on this topic.Still I need more clarity on this.

It is rt(4+rt(4-something)). Now this ‘something’ is within a rt sign, so cannot be negative by definition. Hence, it must be rt(4+rt(less than 4)) which is less than rt(4+rt4).

What about x<-2 in the example from CAT 2005?

Never mind just read the square root function post.

Since it is within a square root sign, it is treated as positive only ðŸ™‚

regards

J

Could you please help me understand how you found the lower limit i.e x should be greater than 4/9. I did refer to the previous post as well.But I am not clear with it.

Thanking you in advance.

Could you please help me understand how you got the lower limit as greater than 4/9. I did try going through the previous post on this topic.Still I need more clarity on this.

1/[2+1/(4+something positive)]

= 1/[2 + (less than 1/4)]

= 1/[less than 2.25]

= (greater than 1/2.25)

= (> 4/9)

regards

J

Could you please help me understand how you found the lower limit i.e x should be less than root(4+root(4)). In cat 2005 qstion?

It is rt(4+rt(4-something)). Now this ‘something’ is within a rt sign, so cannot be negative by definition. Hence, it must be rt(4+rt(less than 4)) which is less than rt(4+rt4).

regards

J

how do we solve second question using “x” variable on RHS

Extremely painfully! Which is why this approach instead. If you have to do that kind of method, leave the question.

regards

J