# Recursive Expressions – 2

## 10 thoughts on “Recursive Expressions – 2”

1. rk1 |

What about x<-2 in the example from CAT 2005?

• rk1 |

Never mind just read the square root function post.

• Since it is within a square root sign, it is treated as positive only ðŸ™‚
regards
J

2. Savio Poulose |

Could you please help me understand how you found the lower limit i.e x should be greater than 4/9. I did refer to the previous post as well.But I am not clear with it.

3. Savi |

Could you please help me understand how you got the lower limit as greater than 4/9. I did try going through the previous post on this topic.Still I need more clarity on this.

• 1/[2+1/(4+something positive)]
= 1/[2 + (less than 1/4)]
= 1/[less than 2.25]
= (greater than 1/2.25)
= (> 4/9)

regards
J

4. Aron |

Could you please help me understand how you found the lower limit i.e x should be less than root(4+root(4)). In cat 2005 qstion?

• It is rt(4+rt(4-something)). Now this ‘something’ is within a rt sign, so cannot be negative by definition. Hence, it must be rt(4+rt(less than 4)) which is less than rt(4+rt4).

regards
J

5. sejal |

how do we solve second question using “x” variable on RHS

• Extremely painfully! Which is why this approach instead. If you have to do that kind of method, leave the question.

regards
J